Masala #0729

Xotira 16 MB Vaqt 1000 ms Qiyinchiligi 10 %
3.5 (Baholar 16)
14

  

Toq or juft

Sizga n(n0)n (n≥0) butun soni berilgan. U mana bu ifodaga teng:

n=a1bk1+a2bk2++ak1b+ak.n=a_1*b^{k-1}+a_2*b^{k-2}+\dots+a_{k-1}*b+a_k.

Bunga misol qilishimiz mumkin,
b=17,k=3,a=[11,15,7]b=17,k=3, a=[11,15,7] bo'lsa,
n=11172+1517+7=3179+255+7=3441n=11*17^2+15*17+7=3179+255+7=3441.
NN juft yoki toq ekanligini aniqlang.


Kiruvchi ma'lumotlar:

Birinchi qatorda ikkita butun bb va k(2b100,1k105)k (2≤b≤100, 1≤k≤105).
Ikkinchi qatorda a1,a2,,ak(0aib)a_1,a_2, \dots ,a_k (0≤a_i≤b)


Chiquvchi ma'lumotlar:

Chiqish faylida yagona qatorda, agar nn juft bo'lsa, "even" deb chop eting. Aks holda "odd" deb chop eting.


Misollar
# input.txt output.txt
1
13 3
3 2 7
even
2
10 9
1 2 3 4 5 6 7 8 9
odd
Izoh:

Birinchi misolda n=3132+213+7=540n=3*13^2+2*13+7=540 demak nn juft son

Ikkinchi misolda n=123456789n=123456789 demak nn toq son

Yechimini yuborish
Bu amalni bajarish uchun tizimga kiring, agar profilingiz bo'lmasa istalgan payt ro'yxatdan o'tishingiz mumkin